A survey by the National Retail Federation found that women spend on average $14

Question

A survey by the National Retail Federation found that women spend on average $146.21 for the Christmas holidays. Assume the population standard deviation is $29.44. Find the percentage of women who spend less than $160.00. Assume the variable is normally distributed. Draw a large graph and label all points and areas. The average number of pounds of meat that a person consumes per year is 218.4 pounds. Assume that the population standard deviation is 25 pounds and the distribution is normally distributive. If a sample of 40 individuals is selected, find the probability that the mean of the sample will be less than 224 pounds per year. Draw a large graph and label all points and areas. Of the members of a bowling league, 10% are widowed. If 200 bowling members are selected at random, find the probability that 10 or more will be widowed. Use the Normal Approximation tc the binomial. Draw a large graph and label all points and areas. A survey of 30 adults found that the mean age of a person's primary vehicle is 5.6 years. Assume that the population standard deviation is 0.8 year. Find a 99% confidence interval to estimate the unknown population mean. Draw a large graph and label all points and areas. A researcher reports that the average salary of assistant professors is more than $42,000 per year. A sample of 30 assistant professors has a mean salary of $43, 260 per year. At a alpha = 0.05 significance level test the claim that assistant professors earn more than $42,000 per year. The population standard deviation is $5, 230. State the null and alternative hypotheses. Draw a large graph and label all points and areas.

Explanation / Answer

Hi Chegg allows us to answer 1 question at a time. I will give you the answer to q1

We need to find P(X<160), given Mean = 146.21 and SD = 29.44

Z = (X-Mean)/SD = (160-146.21)/29.44 = 0.468

Therefore P(Z<0.468) can be found by using the Excel function NORMSDIST(0.468) = 0.68028

Therefore the % of women who spend less than $160 = 68.028%

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