A test statistic used to compare group means is c = y_i^bar - y_j^bar/Squareroot

Question

A test statistic used to compare group means is c = y_i^bar - y_j^bar/Squareroot E(1/n_i + 1/n_j) In Scheffe's test, the value E is the pooled variance from the groups i and j the mean squared error from the ANOVA on all groups, not just groups i and j the overall variance of the responses y_ij the mean error between groups the sample variance of the predictors, s_x^2 This expression sigma_i=1^k (n_i - 1)s_i^2/sigma_i=1^k (n_i - 1) is the definition of sum of squared errors sum of squares between groups mean squared error (within groups) mean square between groups total sum of squares

Explanation / Answer

(2)

   Option A : The pooled variance from the groups I and j.

Pooled variance known as combined, composite, or overallvariance is a method for estimating variance of several different populations when the mean of each population may be different, but one may assume that the variance of each population is the same.

(3) Option C : Mean squared error (within groups)

The test is based on two estimates of the population variance (2). One estimate is called the mean square error (MSE) and is based on differences among scores within the groups.

   

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.