Junior wanted to estimate the mean amount of a certain chemical that his factory

Question

Junior wanted to estimate the mean amount of a certain chemical that his factory uses per day. He selected 12 days at random from the calendar and monitored use of that chemical for those days. His sample mean turned out to be 52.0 gallons daily, with a sample standard deviation of ± 7.7 gallons daily.

A 95% confidence interval estimate of the daily use of this chemical would take the form 52.0 ± margin of error.

Calculate the margin of error = Answer gallons daily (to at least two decimal places)

Explanation / Answer

Margin of error is given by z*s/sqrt(N)

z for 95% is given by 1.96

s=7.7 and N=12

Thus putting these values in formula gives, 1.96*7.7/sqrt(12)=4.3566

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