5. Crime and Strangers: The accompanying table lists survey results obtained fro
ID: 3226207 • Letter: 5
Question
5. Crime and Strangers: The accompanying table lists survey results obtained from a random sample of different crime victims. At the 0.05 significance level, test the claim that the type of crime is independent of whether the criminal is a stranger.
Homicide
Robbery
Assault
Criminal was a Stranger
12
379
727
Criminal was acquaintance or relative
39
106
642
a. Identify the explanatory and response variable.
b. State the hypothesis (in words, in this context) to be tested with a chi-square test on the data in this table.
c. Use technology to calculate the expected values, test statistic, and p-value. Report the test statistic and p-value.
Test statistic: p-value:
d. Do the sample data provide evidence that the type of crime is independent of whether the criminal is a stranger., at the 0.05 significance level?
e. How might the results affect the strategy police officers use when they investigate crimes?
Homicide
Robbery
Assault
Criminal was a Stranger
12
379
727
Criminal was acquaintance or relative
39
106
642
Explanation / Answer
(a)
Explanatory variable: The criminal is a stranger or not
Response variable: Tyep of crime
(b)
H0: The type of crime is independent of whether the criminal is a stranger.
Ha: The type of crime is not independent of whether the criminal is a stranger.
(c)
Following is the output of the chi square test generated by excel:
d:
P-value is 0.0000
Since p-value is less than 0.05 significance level so we cannot conclude that the type of crime is independent of whether the criminal is a stranger.
(e)
According to type of crime police officer should try to find that whether the criminal is in relation with crime victims.
Chi-square Contingency Table Test for Independence Homicide Robbery Assault Total Criminal was a Stranger Observed 12 379 727 1118 Expected 29.93 284.64 803.43 1118.00 Criminal was acquaintance or relative Observed 39 106 642 787 Expected 21.07 200.36 565.57 787.00 Total Observed 51 485 1369 1905 Expected 51.00 485.00 1369.00 1905.00 119.33 chi-square 2 df 1.22E-26 p-valueRelated Questions
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