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The shear strength of each of ten test spot welds is determined, yielding the fo

ID: 3224741 • Letter: T

Question

The shear strength of each of ten test spot welds is determined, yielding the following data (psi):

(a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using the method of maximum likelihood. (Round your answers to two decimal places.)


(b) Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 95th percentile in terms of and ? Now use the invariance principle.] (Round your answer to two decimal places.)
? psi

362 392 415 389 362 358 375 409 367 370

Explanation / Answer

Sample A

X-Xbar

(X-Xbar)2

362

-17.9

320.41

392

12.1

146.41

415

35.1

1232.01

389

9.1

82.81

362

-17.9

320.41

358

-21.9

479.61

375

-4.9

24.01

409

29.1

846.81

367

-12.9

166.41

370

-9.9

98.01

Total =3799

0

3716.9

Sample mean µ = 3799/10 =379.9

Sample S.D = sqrt( 3716.9/10)

                        = 19.2793

Sample A

X-Xbar

(X-Xbar)2

362

-17.9

320.41

392

12.1

146.41

415

35.1

1232.01

389

9.1

82.81

362

-17.9

320.41

358

-21.9

479.61

375

-4.9

24.01

409

29.1

846.81

367

-12.9

166.41

370

-9.9

98.01

Total =3799

0

3716.9

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