The table above shows responses to a travel survey by 1500 respondents. Equal nu
ID: 3224336 • Letter: T
Question
The table above shows responses to a travel survey by 1500 respondents. Equal numbers of respondents said they prefer vacationing in Manhattan and Miami. More respondents (900) preferred sightseeing to laying on a beach (600). Only 10 respondents indicated they prefer the beach and visiting Manhattan; conversely 160 respondents indicated they prefer sightseeing and visiting Miami. Given this information, what is the probability that a randomly selected vacationer would choose sightseeing, given they have already chosen to visit Miami? Round your answer to three decimal places.
Beach Sightseeing Manhattan 10 740 750 Miami 590 160 750 600 900 1500Explanation / Answer
Solution:-The probability that a randomly selected vacationer would choose sightseeing, given they have already chosen to visit Miami = 0.21333
Total number of vacationer who has choosen MIami = 750.
Number of vacationer who has choosen sightseeing and Miami = 160
The probability that a randomly selected vacationer would choose sightseeing, given they have already chosen to visit Miami = 160/750 = 0.21333
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