The manufacturer of a new line of ink-jet printers would like to include as part
ID: 3224239 • Letter: T
Question
The manufacturer of a new line of ink-jet printers would like to include as part of its advertising the number of pages a user can expect from a print cartridge. A sample of 10 cartridges revealed the following number of pages printed.
3,030
2,560
2,550
2,500
3,060
2,500
2,110
3,760
2,950
2,510
What is the point estimate of the population mean? (Round your answer to the nearest whole number.)
Develop a 95% confidence interval for the population mean. (Round your answers to 2 decimal places.)
Confidence interval for the population mean is between ______ and _____
The manufacturer of a new line of ink-jet printers would like to include as part of its advertising the number of pages a user can expect from a print cartridge. A sample of 10 cartridges revealed the following number of pages printed.
3,030
2,560
2,550
2,500
3,060
2,500
2,110
3,760
2,950
2,510
a.What is the point estimate of the population mean? (Round your answer to the nearest whole number.)
Estimated population mean: b.Develop a 95% confidence interval for the population mean. (Round your answers to 2 decimal places.)
Confidence interval for the population mean is between ______ and _____
Explanation / Answer
a.
point estimate of the population mean =2753
b.
Confidence Interval
CI = x ± t a/2 * (sd/ Sqrt(n))
Where,
x = Mean
sd = Standard Deviation
a = 1 - (Confidence Level/100)
ta/2 = t-table value
CI = Confidence Interval
Mean(x)=2753
Standard deviation( sd )=459.8079
Sample Size(n)=10
Confidence Interval = [ 2753 ± t a/2 ( 459.8079/ Sqrt ( 10) ) ]
= [ 2753 - 2.262 * (145.404) , 2753 + 2.262 * (145.404) ]
= [ 2424.096,3081.904 ]=(2424.10,3081.90)
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