**All three of these are meant to be done in R** 1. There were 59 accidents duri

Question

**All three of these are meant to be done in R**

1. There were 59 accidents during the weekends among 114 bicycle accidents. A researcher tested if the population proportion of bicycle accidents during the weekends is less than .60 . Report the p-value with continuity correction.

2. (dataset: HairEyeColor) Determine the proportion of male who has brown hair and green eye.

3. (dataset: HairEyeColor) Report the p-value to test if female is more than half in the group.

Even if you can't answer all three I would appreciate any help. Thanks!

Explanation / Answer

Solution1:

null hypothesis:

Ho:p=0.6

Alternative Hypothesis:

Ha:p<0.60

code:

prop.test(59, 114, p=.6, alt="less", correct=true)

output:

   1-sample proportions test with continuity correction

data: 59 out of 114, null probability 0.6
X-squared = 2.8951, df = 1, p-value = 0.04442
alternative hypothesis: true p is less than 0.6
95 percent confidence interval:
0.0000000 0.5974791
sample estimates:
p
0.5175439

p>0.05

Fail to reject null hypothesis

Accept null hypothesis

Conclusion:

There is no sufficient evidence at 5% level of significance to support the claim that

he population proportion of bicycle accidents during the weekends is less than .60

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