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it is not possible to tell from the information provided. 3. Each person in a ra

ID: 3223887 • Letter: I

Question

it is not possible to tell from the information provided. 3. Each person in a random sample of 2000 ikely voters" (as defined by a professional polling organization) was questioned about his or her political views. Of those surveyed, fet that the economy state was the most urgent national concern. A99% confidence interval proportion p of all likely voters that feel the economys state most urgent national concern is given by (use four 0.624 to 0.663. 0.627 to 0.681 0.615 to 0.672. 0.606 to 0.680 in the community concerning a property tax levy on the coming local They randomly selected B50 residents in the community and contacted supported the property tax levy Let p represent the proportion in the community that support the property tax levy. How large a sample 4. A local board of education conducted a survey of residents them by telephone. Of the B50 residents surveyed, 410 would you need to estimate p with margin of emor 0.04 with 95% confidence? Assume that you don't know anything about the value ofP in 1037 423 s. A veterinarian studying causes of enterouths in horses suspects feeding too much alrara may be a aprit. The veterinarian hypothesizes that more than two thirds of al horses wer entero are proper hypothesis statement Hos p 0.67, Ha: p 0.67 Ho: p 0.67, Ha: p 0.67 0.67, H.: o 67. to the National Institute on Alcohol Abuse and Alcoholism, and the Institutes of Health, of college students natonwide engageinbinge drinking behavior having nve or more drinks one occasion during the past two weeks. A college president wonders the proportion at her binge the in Desting her suspicion in drinking. The colege president is ore interested ofstudents at her colege that hinge drink is lower than the national prooorton ofo41. Her stan tests the hypotheses no: p 0.41. He P

Explanation / Answer

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Here' correct attempt on Q4)

pcap = 410/850 = .482

Z = 1.96

Margin of error = .04

.04 = 1.96*sqrt(.482*.518/n)

.04^2 = (1.96^2)*(.482*.518/n)

n = (.482*.518)*(1.96/.04)^2

n ~= 601