The following data represent the results from an independent-measures study comp

Question

The following data represent the results from an independent-measures study comparing two treatment conditions. Treatment 10 G- 50 EX2 306 T 35 T 15 SS 10 SS Use an independent measures t test with o 05 to determine whether there is a significant mean difference between the two treatments. se three decimal places for the standard error and critical values, two for the pooled variance and t statistic. Us the Distributions tool below to find the critical value.) see Pooled Estimated t Statistic Variance Standard Error Value Critical Values Conc O Reject the null hypothesis. There is a significant difference between the two treatments. O Fail to reject the null hypothesis. There is no significant difference between the two treatments. O Reject the null hypothesis. There is no significant difference between the two treatments. O Fail to reject the null hypothesis. There is a significant difference between the two treatments. Use an ANOVA with o .05 to determine whether there is a significant mean difference between the two treatments. Degrees of Source of Variation Sum of Squares Freedom Mean Square Between treatments Within treatments Tota

Explanation / Answer

T Test
pooled variance, sp2 = [(n1-1)*s12 +(n2-1)*s22]/[n1+n2-2] = [(4)*(10/4)+ (4)*(6/4)]/[5+5-2] = 2

SE = sp * sqrt((1/n1)+(1/n2)) = sqrt(2)*sqrt((1/5)+(1/5)) = 0.894

t = [mean(x1) - mean(x2)]/SE = (7-3)/0.894= 4.472

df = n1+n2-2 = 8, p = .002

conclusion: Reject the null hypothesis. There is a significant difference between the two means

Anova

R code and output:

Critical F value = 5.318

Conclusion: Reject the null hypothesis. There is a significant difference between the two treatments

Source of variation Sum of squares Degrees of freedom Mean Square F Between treatments 40 1 40 20 Within treatments 16 8 2 Total 56 9

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