OP /Student PlayerTe aspx testid 57692740 O OneLogin B Unit 6 Estimating values
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OP /Student PlayerTe aspx testid 57692740 O OneLogin B Unit 6 Estimating values Using Takea Test-Leexiong C In A Trial or 17 Patients Who C search Textbook solutions Ich E Rounding Numbers Calculator Hro How to Take Screenshots in Wi dvorites. Lee XIong & 4'15/17 2:24 PM MAT 220.3 Statistics IDMoD4 ONLINE (36 3Di1701 Test: POST UNIT 6 TEST Ch. 9 Submit Tesl This Question 1 pt This Test: 8 pts possible 3 of 8 complete) Question Help An interactive poll found that 335 of 2.2 adults aged 18 or older have at least one tattoo. 01 limate for th proportio of adults wh e tatlo a Po (b) Construct a 95% confidence interval for the proportion of adults with at least ona tattoo. struct a 99% forth ortion of adul tattoo (d) What is the effect of incraasing the level of confidence on the width of the interval? (a) Round to three decimal places as needed b) Construct the 95% confidence interval. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. O Lower bound Upper bound (Round to three decimal places as needed.) O B. The requirements for constructing a confidence interval are not satisfied (c) Construct the 99% confidence interval. Select the correct choice below and, if necessary, filin the answer boxes to oamplete your choice. O Lower bound Upper bound decimal p O B. The requirements for constructing a confidence interval are not satisfied. (d) Choose the correct answer below. O A. Increasing the level of confidence narrows the interval Click to select your answer(s). 100% .24 AM & e e 4/15/201Explanation / Answer
Answer in detail below:
a)
pcap = 335/2201 = .1522
b)
The 95% CI is given by:
Z = 1.96
So, pcap+/- Z(sqrt(p*p'/n)
=.1522 +/- 1.96*sqrt(.1522*.8478/2201)
=.1372 to .1672
c)
The 99% CI is given by:
Z = 2.575
So, pcap+/- Z(sqrt(p*p'/n)
=.1522 +/- 2.575*sqrt(.1522*.8478/2201)
=.1325 to .1719
d) If you increase the level of confidence then Z increases which in turn increases the Margin of error, which incrreases the Width of the confidence interval
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