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Let X be a normal random variable with mean 199 units and standard deviation 6 u

ID: 3221768 • Letter: L

Question

Let X be a normal random variable with mean 199 units and standard deviation 6 units. Answer the following questions, rounding your answers to two decimal places: (a) What is the probability that X will be within 13 units of the mean? (b) The probability is 0.09 that X will be more than how many units? Assume that women's weights are normally distributed with a mean given by mu=143 lb and a standard deviation given by sigma=29 lb:... If 74 women are randomly selected, find the probability that they have a mean weight below 113?

Explanation / Answer

X be a normal random variable with mean 199 units and standard deviation 6 units.

µ = 199 and = 6

Applying transformation into standard normal variate we can solve this problem.

SNV = Z = (X - µ)/

(a) What is the probability that X will be within 13 units of the mean?

= P [ 186 < x < 212]

= P[(186-199)/6 < Z < (212-199)/6]

= P [ -2.17 < Z < 2.17]

Using normal distribution table we can find the probabilities

= 2 * Area between zero to 2.17 [Since normal distribution is symmetrical]

= 2*0.4850 = 0.97

Therefore, the probability that X will be within 13 units of the mean is 0.97.

(b) The probability is 0.09 that X will be more than how many units?

Appling the values in SNV

We have to find the value of x

P[X > 199] = 0.09

From normal distribution table, the correponding value of z is 1.34

Therefore, (X -199)/ 6 = 1.34

which gives x = (1.34*6) + 199 = 207.

Therefore the X will be more than 207 units to have the probability of 0.09.

Assume that women's weights are normally distributed with a mean given by mu=143 lb and a standard deviation given by sigma=29 lb:... If 74 women are randomly selected, find the probability that they have a mean weight below 113?

Answer:

µ = 143 and = 29

Probability that they have a mean weight below 113 = P [ x < 113]

= P [z < (113-143)/29]

= P[z < -1.0345]

Using normal distribution table,

= Area from -infinity ot zero - Area from zero to -1.0345

= 0.5 - 03485

= 0.1515

Therefore, Probability that they have a mean weight below 113 is 0.1515.

For, 74 women,

=74 * 0.1515 = 11.211 ~ 11

11 women will have weight below 113.

Hope this will help.