Attempts: 0 Average: 1/3 2. observing differences between between-treatments var
ID: 3221603 • Letter: A
Question
Attempts: 0 Average: 1/3 2. observing differences between between-treatments variance and within-treatments Aa Aa variance Dr. Nicholas Guegen uses observational methods to study how certain kinds of environmental stimuli influence human behavior. In one study, he manipulated the volume of music played in bars to see how it would impact patrons drinking behaviors. Trained observers recorded the number of drinks ordered by several patrons in two establishments. The sound level was manipulated in both establishments, and all observations occurred over three Saturday nights. Dr. Guegen used two sound levels in his study: a normal sound level of 72 dB, which is similar to traffic noise on a busy street, and a louder high-volume level of 88 dB, which is similar to noise from a lawn mower. You decide to replicate this study. The null hypothesis is that there is no difference between the mean number of drinks ordered among patrons experiencing the high-volume noise level of 88 dB and the mean number of drinks ordered among those experiencing the normal noise level of 72 dB. The alternative hypothesis is that there is a difference between the mean number of drinks ordered among patrons experiencing the louder noise level of 88 dB and the mean number of drinks ordered among those experiencing the normal noise level of 72 dB Below are the graphs of two possible data sets. The horizontal axes display the number of drinks ordered, while the vertical axes display the number of observed patrons who ordered that many drinks. Use these graphs to answer the questions that follow. High volume (88 dbl High volume (88 db) Number of Drinks ordered Number of Drinks ordered Iormal 72 db) Ilormal 72 db) Number of Drinks ordered Number of Drinks orderedExplanation / Answer
The spread of the data is greater than data set B so variability of data set B is higher than data set A.
First option is correct.
F ration is ratio of between treatments variance and within treatment variance and since between treatments variance is greater than within treatment variance so F ration will be greater than 1.
That is option "substantially larger than 1.00" is correct.
So null hypothesis will be rejected.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.