4. Another one of your administrators believes that the true average (mean) wait

Question

4.   Another one of your administrators believes that the true average (mean) wait time to see an ER Doctor in the urban location is less than 100 minutes.

.     Using the TI-83/84, and the 5 step hypothesis testing procedure, determine

whether the data provide evidence to support your manager’s belief

( use alpha =.05)

Can someone please help me solve this using a TI-83?

Location Rating Time Cost Urban 1 90 2300 Urban 1 94 2500 Urban 1 98 2200 Urban 1 98 2900 Urban 1 99 2000 Urban 1 85 2100 Urban 1 78 2000 Urban 2 100 2600 Urban 2 89 2100 Urban 2 97 2800 Urban 2 102 2900 Urban 2 101 3100 Urban 2 97 2000 Urban 2 95 2200 Urban 2 100 2500 Urban 2 93 2700 Urban 4 113 3000 Suburban 1 68 3200 Suburban 1 76 3300 Suburban 1 83 2800 Suburban 1 69 3000 Suburban 1 79 3100 Suburban 1 98 3400 Suburban 1 110 4000 Suburban 2 88 2900 Suburban 2 90 3200 Suburban 2 98 3100 Suburban 2 92 3900 Suburban 3 103 3300 Suburban 3 120 2500 Rural 1 98 4500 Rural 2 112 2800 Rural 2 121 3900 Rural 3 90 4000 Rural 3 102 3800 Rural 3 123 3500 Rural 3 102 3000 Rural 3 119 4400 Rural 4 110 2500 Rural 5 99 3900

Explanation / Answer

Solution:

Here, we have to use one sample t test for population mean.

H0: µ = 100 versus Ha: µ < 100

= 0.05

The test statistic formula is given as below:

t = (Xbar - µ)/[SD/sqrt(n)]

From the given data set, we have

(Consider only urban data)

Xbar = 95.82

SD = 7.68

Sample size = n = 17

Degrees of freedom = n - 1 = 16

Test statistic = t = (95.82 – 100)/[7.68/sqrt(17)]

Test statistic = t = -2.2413

Critical value = -1.7459

p-value = 0.0198

= 0.05

p-value <

So, reject the null hypothesis

There is sufficient evidence to conclude that an ER Doctor in the urban location is less than 100 minutes.

Using Ti-84 commands:

START

Press STAT

Use scroll right to the TESTS

Then scroll down to 2: T-Test

ENTER

Input Data

ENTER Data one by one

Calculate

Press Enter

Output

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