Let X be random variable with probability mass function and the probability mass

Question

Let X be random variable with probability mass function and the probability mass function of y= 2x +3 y=x^2 A sample of size 49 was drawn from a normally distributed population, and the 99percentage CI for mu is (-2, 10). Find the sample mean X Find the sample variance s^2 Two scientists claimed that a new treatment is more effective than the standard treatment for prolonging the lives of terminal cancer patients. The standard treatment has been in use for a long time, and from records in medical journals, the mean survival period is known to be 4.2 years. The new treatment is administered to 25 patients and their duration of survival recorded. The mean and the standard deviation for the sample with the new treatment are found to be 5.5 and 1.0 years, respectively. Is it really a more effective treatment? Formulate the null and alternative hypotheses for the claim? Find the critical value for significance level alpha= .05. Find the test statistics Draw conclusion

Explanation / Answer

Sol

to find sample mean

-2 is lower limit

10 is upper limit

sample mean -margin of error=-2----(1)

sample mean_margin of error=10-----(2)

2(samplemean)=2+10

sample mean=4

substitute in eq 1 to get margin of error

4-margin of error=-2

6=margin of error

margin of error=z (s)/sqrt(n)

6 =2.576(s)/49

s=6*49/2.576=114.13

s2 =13025.7561

sample varinace=13025.7561

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.