During the 2013 season, a baseball player hit a total of 47 home runs in the 161

Question

During the 2013 season, a baseball player hit a total of 47 home runs in the 161 games he played,distributed as follows: he had 3 games during which he hit 2 or more home runs; he had 39 gamesduring which he hit 1 home run, and he had 119 games during which he did not hit a home run.
(a) On a given day that season, what is the probability that the player did not hit a home run?

(b) Does the observed number of home runs per game approximately follow a Poisson distribution

with parameter = 47/161?

.

GIVE DETAILED EXPLANATION FOR B PLEASE

Explanation / Answer

a) the probability that the player did not hit a home run = 119 / 161 = 0.739

b) Yes, given context is not suitable for poisson distribution.

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