Please provide explanation Use this information to answer the following 5 relate

Question

Please provide explanation

Use this information to answer the following 5 related questions:

Family transportation costs are usually higher than most people believe because those costs include car payments, insurance, fuel costs, repairs, parking and public transportation. Twenty randomly selected families in four major cities are asked to use their records to estimate a monthly figure for transportation cost. The sample data are given here.(web file:Transportation)

Atlanta

New York

Los Angeles

Chicago

850

450

1050

740

680

725

900

650

850

600

1250

975

800

375

980

750

875

700

800

800

Using ANOVA, the goal is to test whether there is significant difference in monthly transportation costs for families living in these cities. Use the following notations:

1:   The mean transportation cost in Atlanta

2:   The mean transportation cost in New York

3:   The mean transportation cost in Los Angeles

4:   The mean transportation cost in Chicago

Question 9

What is the null hypothesis?

Select one:

a. 1=2=3=4

b. 3>2>2>4

Question 10

What is the value of the test statistic? Rounded to 2 decimal points

Answer::

Question 11

What is the p-value of the test? Rounded to 4 decimal points

Answer:

Question 12

At 5% level of significance, what is the critical value? Rounded to 2 decimal points.

Answer:

Question 13

At the 5% level of significance,

Select one:

a. At least one mean transportation cost is different

b. At least two mean transportation costs are different

Atlanta

New York

Los Angeles

Chicago

850

450

1050

740

680

725

900

650

850

600

1250

975

800

375

980

750

875

700

800

800

Explanation / Answer

following ANOVA information is generated from the given data

answer(9) right choice is a. 1=2=3=4

Null hypothesis is used in statistics that proposes that no statistical significance exists in a set of given observations.Null hypothesis attempts to show that no variation exists between variables or that a single variable is no different than its mean.

answer(10) F=8.35

here we use F-test for equality of more than two means.

answer(11) p-value=0.0014 ( look anova table above)

answer(12) critical value=F(0.05,3,16)=3.24

answer(13) right choice is a.At least one mean transportation cost is different

since the calculated F=8.35 is more than critical F=3.24 so we fail to accept null hypothesis in favor of alternate hypothesis.

here alternate hypothesis H1: At least one mean transportation cost is different

Source DF Sum of Squares Mean Square F Value Pr > F Model 3 456630.0000 152210.0000 8.35 0.0014 Error 16 291770.0000 18235.6250 Corrected Total 19 748400.0000

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