This is similar to the last question. In genome DNA sequence, there are GC-rich

Question

This is similar to the last question. In genome DNA sequence, there are GC-rich regions (R) and normal (N) regions. The genome has 30% GC-rich regions and the rest are normal regions. Figure A is the probabilistic model of these regions. The transition probabilities are shown next to the arrows, and the emission probabilities are shown in the box. Suppose you have a DNA sequence AGTAGCTG, determine the probabilities that your entire sequence is from a Normal region. (use scientific notation, e.g. A*1^a(-2), means A times 10 to the negative second power. The unit part write as 10^(B), B represent the power. Use 3 significant digits)

Explanation / Answer

Assume the two regions Normal and GC-Rich are independent.

Given the sequence AGTAGCTG, we have to find probability entire sequence is from a Normal region.

This is equivalent of present state being N and 8 subsequent positions being N as well.

p = .98*.3*.2*.3*.3*.2*.2*.3*.2 = .98*.34*.24 = 5.579 * 10-6

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