Q1. How we solve it Q2. How we solve it (e) there is a 95% probability that the

Question

Q1. How we solve it

Q2. How we solve it

(e) there is a 95% probability that the true average earnings are between $3525 and $4425 for all students. 3. The diameter of ball bearings are known to be normally distributed with unknown mean and variance. A random sample of size 25 gave a mean 2.5 cm. The 95% confidence interval had length 4 cm. hen (a) The sample variance is 5.102. (b) The sample variance is 26.03. (c) The sample variance is 4.84 (d) The population variance is 34.16. Me The sample variance is 23.47.

Explanation / Answer

Q2)

n=50

Mean = 12.68

Stdev = 6.83

CI = (11.09,14.27)

Z = ?

Margin of error = (12.68-11.09) = 1.58

So, 1.58 = Z*6.83/sqrt(50)

Z = 1.58*Sqrt(50)/6.83 = 1.635 which is nearly 90% Confidence interval.

Level of confidence = 90%

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