I am having trouble with the last part. The following data represent the muzzle
ID: 3218854 • Letter: I
Question
I am having trouble with the last part.
The following data represent the muzzle velocity (in feet per second) of shells fired from a 155-mm gun. For each shell, two measurements of the velocity were recorded using two different measuring devices, resulting in the following data Observation 1 2 3 4 5 6 A 794.9 793.5 793.3 791.1 790.3 793.9 B = 790.5 800.7 801.0 791.6 792.4 794.0 Why are these matched-pairs data? The same round was fired in every trial All the measurements came from rounds fired from the same gun. Two measurements (A and B) are taken on the same round The measurements (A and B) are taken by the same instrument. Is there a difference in the measurement of the muzzle velocity between device A and device B at the alpha = 0.01 level of significance? What is your conclusion regarding H_0? Do not reject H_0 Reject H_0 Construct a 99% confidence interval about the population mean difference Compute the difference as device A minus device B. Interpret your results. The confidence interval is (, ) (Round to three decimal places as needed.)Explanation / Answer
The statistical software output for 99% confidence interval is:
Paired T confidence interval:
D = 1 - 2 : Mean of the difference between A and B
99% confidence interval results:
Hence,
The confidence interval is (-9.784, 5.384)
Difference Mean Std. Err. DF L. Limit U. Limit A - B -2.2 1.88078 5 -9.7836036 5.3836036Related Questions
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