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ID: 3218092 • Letter: R
Question
remaining for each question partonly ehangesryou submt or change te answer. you Mubmit answers by Rueiliun parts the number of. nonstudents. One of the of 57 A study of identity theft looked at her well consumers pretect themselves from this increasingly prevalent crime. The behaviors of s4 college students were compared with the behaviers "when asked to create a I have vsed ether my mother'smaiden name, er my pers name, or my birth date or the last four digits.f my social securty num numbers. For 24 wth this statement while 27 of the nanstudents apreed. series of (a) Display the data in a Agreed ET perform the chi-square test. (Round your r to three decimal places and reund your P-value to four decimal places.) w. ennat conclude at the swi level that tudents and nonstudents druer in hereroonse o we can contide the level than students and nonstudents dner in the ,..ren. to this question. (b) kaasaya. u. data using the methods for comparing twe proportions that we studied in the previout chapter, campare the and verry that the cha-square statuetk is the square of the r statistie. (Test students whe agreed minus nenteudents who agreed, Reund veur z to two decimal places round yeur feur decimal places.) and P-value te The students in this study were junior and wenior cellege students from twe sections of. eurre in marketiny at a large nertheastern university. The nonstudents were a Greap of individwe who wereExplanation / Answer
Solution:-
b)
x1 =24, n1 = 64
p2 = 24/64 = 0.375
x2 = 27, n2 = 57
p2 = 27/57 = 0.474
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: P1 = P2
Alternative hypothesis: P1 P2
Note that these hypotheses constitute a two-tailed test. The null hypothesis will be rejected if the proportion from population 1 is too big or if it is too small.
Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method is a two-proportion z-test.
Analyze sample data. Using sample data, we calculate the pooled sample proportion (p) and the standard error (SE). Using those measures, we compute the z-score test statistic (z).
p = (p1 * n1 + p2 * n2) / (n1 + n2)
p = 0.4215
SE = sqrt{ p * ( 1 - p ) * [ (1/n1) + (1/n2) ] }
SE = 0.0899
z = (p1 - p2) / SE
z = - 1.10
where p1 is the sample proportion in sample 1, where p2 is the sample proportion in sample 2, n1 is the size of sample 1, and n2 is the size of sample 2.
Since we have a two-tailed test, the P-value is the probability that the z-score is less than - 1.10 or greater than 1.10.
Thus, the P-value = 0.267
Interpret results. Since the P-value (0.267) is greater than the significance level (0.05), we have to accept the null hypothesis.
From the above test we do not have suffcieint evidence in the favor of the claim that the proportion are different.
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