Suppose the proportion of students retained in 2003 is P03 and the proportion of

Question

Suppose the proportion of students retained in 2003 is P03 and the proportion of students retained in 2004 is P04. A study found a 90% confidence interval for P03 - P04 is (-0.0398, 0.0262). Give an interpretation of this confidence interval. We know that 90% of all random samples done on the population will show that the proportion of students retained in 2003 is between 3.98% less and 2.62% more than the proportion of students retained in 2004. We know that 90% of students retained in 2003 between 3.98% less and 2.62% more than 2004. We know that 90% of students retained in 2004 between 3.98% less and 2.62% more than 2003. We are 90% confident that the proportion of students retained in 2004 is between 3.98% less and 2.62% more than the proportion of students retained in 2003. We are 90% confident that the proportion of students retained in 2003 is between 3.98% less and 2.62% more than the proportion of students retained in 2004.

Explanation / Answer

Here we are finding CI for P03-P04 ie difference of how many retained in P03 compared to P04

So the confidence interval will tell us that we are 90% confident tht the proportion of students retained in 2003 is between 3.98% less and 2.62% more than the proportion of students retained in 2004

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.