10 Use only calc. scientific method.. 17 parts please number answers .. ty Test

Question

10 Use only calc. scientific method.. 17 parts please number answers .. ty

Test the given claim. Assume that a simple random sample is selected from a normally distributed population. Use either the P-value method or the traditional method of testing hypotheses.

Company A uses a new production method to manufacture aircraft altimeters. A simple random sample of new altimeters resulted in errors listed below. Use a 0.05 level of significance to test the claim that the new production method has errors with a standard deviation greater than 32.2 ft, which was the standard deviation for the old production method. If it appears that the standard deviation is greater, does the new production method appear to be better or worse than the old method? Should the company take any action?

What are the null and alternative hypotheses?

A.HO: =32.2ft H1: >32.2 ft

B.H0:>32.2 ft H1:=32.2 ft

C.H0:<32.2 ft H1:=32.2 ft

D.H0:32.2 ft H1:=32.2 ft

E.H0:=32.2 ft H1:32.2 ft

F.H0:=32.2 ft H1:<32.2 ft

Find the test statistic. 2=________(Round to two decimal places as needed.)

Determine the critical value(s). The critical value(s) is/are_______ .(Use a comma to separate answers as needed. Round to two decimal places as needed.)

Since the test statistic is(1)_______the critical value(s),

(2)_______H0.

There is (3)________evidence to support the claim that the new production method has errors with a standard deviation greater than 32.2 ft.

The variation appears to be (4)________than in the past,

so the new method appears to be (5)_______, because there will be

(6)_______altimeters that have errors.

Therefore, the company (7)_______take immediate action to reduce the variation.

Answer accordingly

(1)less than/equal to/between/greater than

(2)reject/fail to reject

(3)sufficient/insufficient

(4)less/about the same/greater

(5)worse/better/similar

(6)the same number of/more/fewer

(7)should not/should

Explanation / Answer

Given that,
population standard deviation ()=32.2
sample standard deviation (s) =57.9882
sample size (n) = 12
we calculate,
population variance (^2) =1036.84
sample variance (s^2)=3362.63133924
null, Ho: =32.2
alternate, H1 : <32.2
level of significance, = 0.05
from standard normal table,left tailed ^2 /2 =19.675
since our test is left-tailed
reject Ho, if ^2 o < -19.675
we use test statistic chisquare ^2 =(n-1)*s^2/o^2
^2 cal=(12 - 1 ) * 3362.63133924 / 1036.84 = 11*3362.63133924/1036.84 = 35.67
| ^2 cal | =35.67
critical value
the value of |^2 | at los 0.05 with d.f (n-1)=11 is 19.675
we got | ^2| =35.67 & | ^2 | =19.675
make decision
hence value of | ^2 cal | > | ^2 | and here we reject Ho
^2 p_value =0.0002

ANSWERS
---------------
null, Ho: =32.2
alternate, H1 : <32.2
test statistic: 35.67
critical value: -19.675
p-value:0.0002
decision: reject Ho
There is enough evidence to support the claim that the new production method has errors with a standard deviation greater than 32.2 ft.

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