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43 49 52 58 68 77 81 88 94 98 45 50 54 61 69 77 84 91 95 100 47 50 54 61 69 77 8

ID: 3217337 • Letter: 4

Question

43 49 52 58 68 77 81 88 94 98

45 50 54 61 69 77 84 91 95 100

47 50 54 61 69 77 85 91 96 102

48 51 56 65 73 78 87 92 96 108

48 51 57 67 76 80 88 93 96 111

What is the percentile for 51?

Find the 80% percentile.

Find the 1st quartile

Find the 38% percentile

Find the 88% percentile

Find the 1st decile.

Find the 90% percentile

What is the percentile for 108?

Find the 3rd decile

Find the 3rd quartile

Find the 45% percentile

Find the 30% percentile

Find the 82% percentile

What is the percentile for 76?

Find the 92% percentile

What is the percentile for 85?

Find the 8th decile

Fin the 2nd quartile

Explanation / Answer

1) 80th percentile

Multiply k percent by the total number of values, n.

0.80 * 50 = 40

If the index obtained is not a whole number, round it up to the nearest whole number .

Counting from left to right (from the smallest to the largest value in the data set), you go until you find the 40th value in the data set. That value is 93, and it’s the 80th percentile for this data set.

2) 1st quartile

It is the half set of the data upto 25 number

43 , 45 , 47 , 48 , 48 , 49 , 50 , 50 , 51, 51 ,52 , 54 , 54 , 56 , 57 , 58 , 61 , 61 , 65 , 67 , 68 , 69 , 69 , 73 , 76

3) 38 percentile

Multiply k percent by the total number of values, n.

0.38 * 50 = 19

If the index obtained is not a whole number, round it up to the nearest whole number .

Counting from left to right (from the smallest to the largest value in the data set), you go until you find the 19th value in the data set. That value is 65, and it’s the 38th percentile for this data set.

4) 88 percentile

Multiply k percent by the total number of values, n.

0.88 * 50 = 44

If the index obtained is not a whole number, round it up to the nearest whole number .

Counting from left to right (from the smallest to the largest value in the data set), you go until you find the 40th value in the data set. That value is 96, and it’s the 88th percentile for this data set.

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