According to data from the U.S. Energy Information Administration, the 35.6 mill
ID: 3217231 • Letter: A
Question
According to data from the U.S. Energy Information Administration, the 35.6 million U. S. households with personal computers were distributed as shown below with regard to geographic location and time per week of computer use. The entries represent millions of households. Find the probability of a randomly selected household being each of the following P(MW intersection High) = 0.0562 0.1882 0.0702 0.0815 0.1798 P(NE intersection Low) 0.0562 0.1882 0.0702 0.0815 0.1798 P(S intersection Low) = 0.0562 0.1882 0.0702 0.0815 0.1798 P(W intersection High) = 0.0562 0.1882 0.0702 0.0815 0.1798 What is the probability that the student will get at least 1 question correct?Explanation / Answer
2)a )P(MWnHigh)=6.7/35.6=0.1882 option B
2b) P(NEnLow)=2/35.6=0.0562 option A
3)P(Snlow)=2.9/35.6=0.0815 option D
4) =6.4/35.6 =0.1798 option E
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