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x paM-Hw ostats02.s17 study a salesperson Project- x Apps C e Secure https l/www

ID: 3217207 • Letter: X

Question

x paM-Hw ostats02.s17 study a salesperson Project- x Apps C e Secure https l/www.webassign.net/web/student/Assignment-Responses/Mast?dep-1599657S Howdy o the eua First State Bank i A MWelis Fargo Perso. a myouINN Bann Co- WebAssign LOG N A topic or recent clinical interest isthe of using drugsto neduce nfarct size patents who have myocardial infarction within the past 24 hours suppose we know that in untreated patients the mean infarct size 25 (ck-g-EQm). Furthermore, patents treatod with a drug the mean infarct Suppose 10. Is there statistical evidence the drug is effective in reducing infarct size? size is 16. (a) What hypotheses should be used to test the claim? Ho H 16 and 16 Ho: u 25 and Ha: 25 We can't answer this question because we aren't given the null value in the statement of the problem. Ho H. 25 and Ha u 25 Ho: a 16 and Ha: 16 Ho: 25 and Ha X 25 Ho 25 and Ha 25 Ho: H 16 and He: 16 (c) Assume the conditions are met, what is the p-value of the test? (d) Assume a 0.01. Should you reject or fail to reject? Reject Fail to reject (e) Complete the conclusion statement below. For the first blank your choices are: provides, does not provide. significance level (l'm asking for the number a) thatthe average infarct size of patients statistical evidence at the "The data treated with the drug is less than

Explanation / Answer

Given that,
population mean(u)=25
standard deviation, =10
sample mean, x =16
number (n)=8
null, Ho: =25
alternate, H1: <25
level of significance, = 0.01
from standard normal table,left tailed z /2 =2.326
since our test is left-tailed
reject Ho, if zo < -2.326
we use test statistic (z) = x-u/(s.d/sqrt(n))
zo = 16-25/(10/sqrt(8)
zo = -2.54558
| zo | = 2.54558
critical value
the value of |z | at los 1% is 2.326
we got |zo| =2.54558 & | z | = 2.326
make decision
hence value of | zo | > | z | and here we reject Ho
p-value : left tail - ha : ( p < -2.54558 ) = 0.00545
hence value of p0.01 > 0.00545, here we reject Ho
ANSWERS
---------------
null, Ho: =25
alternate, H1: <25
test statistic: -2.54558
critical value: -2.326
decision: reject Ho
p-value: 0.00545