A survey of 1, 661 randomly selected adults showed that 511 of them have heard o

Question

A survey of 1, 661 randomly selected adults showed that 511 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 33% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Sample proportion: 0 307646 Test statistic, z: -1.9375 Critical z: plusminus 2.575 P-Value: 0.0527 a. Is the test two-tailed, left-tailed, or right-tailed? Right tailed test Two-tailed test Left-tailed test b. What is the test statistic? z = _____ (Round to two decimal places as needed.) c. What is the P-value? P-value = _____ (Round to four decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. A. H_0: p > 0.33 B. H_0: p notequalto 0.33 C. H_0: p = 0.33 D. H_0: p

Explanation / Answer

Given that,
possibile chances (x)=511
sample size(n)=1661
success rate ( p )= x/n = 0.3076
success probability,( po )=0.33
failure probability,( qo) = 0.67
null, Ho:p=0.33
alternate, H1: p!=0.33
level of significance, = 0.01
from standard normal table, two tailed z /2 =2.58
since our test is two-tailed
reject Ho, if zo < -2.58 OR if zo > 2.58
we use test statistic z proportion = p-po/sqrt(poqo/n)
zo=0.30765-0.33/(sqrt(0.2211)/1661)
zo =-1.9375
| zo | =1.9375
critical value
the value of |z | at los 0.01% is 2.58
we got |zo| =1.938 & | z | =2.58
make decision
hence value of |zo | < | z | and here we do not reject Ho
p-value: two tailed ( double the one tail ) - Ha : ( p != -1.93752 ) = 0.05268
hence value of p0.01 < 0.0527,here we do not reject Ho
ANSWERS
---------------
null, Ho:p=0.33
alternate, H1: p!=0.33
test statistic: -1.9375
critical value: -2.58 , 2.58
decision: do not reject Ho
p-value: 0.05268

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.