There was carried out an investigation to study the toxic effects of mercury. Te

Question

There was carried out an investigation to study the toxic effects of mercury. Ten different concentrations of mercury (0, 1, 5, 10, 50, 100, 200, 300, 400, and 500 mg/L) were compared with respect to their effects on average dry weight (per 100 seven-day-old seedlings). The basic experiment was replicated four times for a total of 70 dryweight observations (seven for each treatment level). The article reported an ANOVA F statistic value of 1.985.

Using a significance level of .05, test the null hypothesis that the true mean dry weight is the same for all 10 concentration levels.

which one? (0, .001, .01, .05, .1) < P < (.001, .01, .05, .1,1)

The conclusion is the following: reject H0 or fail to reject H0

Explanation / Answer

we are given that anova F stat as = 1.985

now we knwo that df numerator = 10-1 = 9

and df denominator = 70-1 = 69 , so looking for this value in the F table we see that t

The p-value is .054187. The result is not significant at p < .05 and hence we fail to reject H0

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