For vectors a and b, both of the same dimensions and based at the same point, sh

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PLEASE RATE ME AND AWARD ME KARMA POINTS IF IT IS HELPFUL FOR YOU Consider an equally spaced partition with n subintervals and choose right end points. ?x = (b - a)/n, x_0 = a, x_k = a + k?x, x_n = b f(x) = x ==> f(x_k) = a + k(b-a)/n. The Riemann sum for such a choice of partition and points x_k is (the terms are f(x_k)?x) n S (a + k(b-a)/n)(b - a)/n = k=1 n...................n S a(b - a)/n + S [(b - a)²/n²] k k=1..............k =1 The first term is just a(b -a)n/n = a(b - a). The second term is [(b -a)²/n²] n(n+1)/2 = ½(b - a)² [n(n+1)/n²] Take the limit as n ->8. lim a(b - a) + ½(b - a)² [n(n+1)/n²] = a(b - a) + ½(b - a)² = ½(b² - a²) n->8 after simplification. I hope this is clear and helpful to you.

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