(a) Prove that the line of intersection of the planes x + 2y - z = 2 and 3x + 2y
ID: 3214380 • Letter: #
Question
(a) Prove that the line of intersection of the planes x + 2y - z = 2 and 3x + 2y + 2z = 7 is parallel to the line x = 1 + 6t, y = 3 - 5t, z = 2 - 4 t. (b) an equation of the plane determined by these two lines. The proof doesn't seem too difficult. n1 = <1, 2, -1> and n2 = <3, 2, 2> and the cross product is <6, -5, 4>, which means that the line of intersection of these two planes is parallel to the line defined by the parametric equations. I don't know how to find the equation of the plane determined by these two lines though (part (b)).Explanation / Answer
This will help u in understand how to find equation a plane determined by two line
http://www.math.washington.edu/~aloveles/Math126Fall2012/sp12m126PlanesAndLines.pdf
check it out..
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