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Write the general forms of the equations of the lines through the point (a) para

ID: 3214194 • Letter: W

Question

Write the general forms of the equations of the lines through the point (a) parallel to the given line and (b) perpendicular to the given line. Given:

Point Line (3/4, 7/8) 5x - 3y = 0

I am not sure how they got to there final answer, this is what they did: used the line equation

(y-7/8)=5/3 (x-3/4)

3(y-y)=10(4x-3)

40x-24y-9=0 Not sure how they got there, definitely skipped a lot of in between steps lol!

Explanation / Answer

slope of line given = dy/dx so differentiating the line equation with respect to x => 5 - 3dy/dx = 0 => dy/dx =5/3 point given = (3/4,7/8) a) line is parallel to given line , so slope is same for both m = 5/3 equation of line :- y - y1 = m(x - x1) y - 7/8 = 5/3(x - 3/4) => 24y - 40x + 9 = 0 b) a) line is perpendicular to given line , so m * m1 = -1 => m1 = - 3/5 equation of line :- y - y1 = m1(x - x1) y - 7/8 = -3/5(x - 3/4)