(graph) y=relative rate of change(0.02 interval) x=time(1.0 interval) from x[0,3
ID: 3214080 • Letter: #
Question
(graph) y=relative rate of change(0.02 interval) x=time(1.0 interval) from x[0,3] value of y=0.04, from x[3,7] valueis lineary=-x starts at 0.04 stops at-0.04, from x[7,8] value of y=-0.04
the graph shows the relative rate of change of the population of an area over a period of several years. suppose that at t=0 years, the area had a population of 86,000 people
a)determine the population at t=9 years
b)determine the net percentage change in population between t=4 and t=8 years. give your response as a percentage, accurate to two decimals, and indicate whether this percentage gives an increase/decrease in population over indicated period of time
c)determine the point in time (value of t) when the population reached 98,000 for the first time, accurate to two decimals
Explanation / Answer
https://www.google.co.in/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&cad=rja&ved=0CDQQFjAA&url=http%3A%2F%2Fwps.aw.com%2Fwps%2Fmedia%2Fobjects%2F11422%2F11696965%2Fanswerstoexercises%2Fsw3_exeol_oddonly.docx&ei=V_v4UIviIMzOrQeX44DAAg&usg=AFQjCNG7jQcWLYjKGxxpI_GGVMreq9Zr6Q&bvm=bv.41248874,d.bmk www.biology.ed.ac.uk/archive/jdeacon/statistics/tress11.html
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