Find the exact value of the area between the graphs of y = cosx and y = e^x for

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e^0=1 and e^x>=1 for x>=0 so we have that the graph of e^x is above cos(x) for the entire interval thus we want to find integral e^x - cos(x) dx with x=0 to 2.4 now this can be computed by breaking it down into 2 integrals, computing each, and subtracting them. integral e^x dx x=0 to 2.4 = e^2.4-e^0=10.0232 integral cos(x) dx x=0 to 2.4=sin(2.4)-sin(0)=sin(1) thus the area is e-10.0232-sin(2.4) which is approxmately 9.3482

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