Yujane S South University Camp x M D Statistics MAT2058 so3 x C Chegg Take a Tes
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Yujane S South University Camp x M D Statistics MAT2058 so3 x C Chegg Take a Test Yujane Lan X In a sample of seven car Secure h ps://www. mathxl.com /Student/PlayerTest aspx?testld 55027879 nv energy DC Connexus Log zenefits Log in I serve fro other bookmarks Watch Statistics I MAT2058 S03 (2) Yujane Lampkin & Quiz: W4: ment 3 Quiz Submit Quiz This Question 5 pts his Quiz: 50 pts possible 6 of 10 (5 complete) Show Work 1E Question Help In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.05. 0.16, 0.07, 0.14. 0.07, 0.18, 0.14. Assuming that this sample is representative of the cars in use, construct a 98% confidence interval estimate of the mean amount of nitrogen-oxide emissions for all cars. If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, can we safely conclude that this requirement is being met? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table Click here to v age 2 of the standard no mal distribution able What is the confidence interval estimate of the mean amount of nitrogen-oxide emissions for all cars? g/m (Round to three decimal places as needed.) Can we safely conclude that the requirement that nitrogen-oxide emissions be less than 0.165 g/mi is being met? O A. Yes, because the confidence interval contains 0.165 g/mi. O B. No, because the confidence interval does not contain 0.165 g/mi. O C. No, it is possible that the requirement is being met, but it is also very possible that the mean is not less than 0.165 g/mi. O D. Yes, we can definitely conclude that the requirement is met for all cars. Click to select your answer(s).Explanation / Answer
Confidence Interval
CI = x ± t a/2 * (sd/ Sqrt(n))
Where,
x = Mean
sd = Standard Deviation
a = 1 - (Confidence Level/100)
ta/2 = t-table value
CI = Confidence Interval
Mean(x)=0.1157
Standard deviation( sd )=0.0513
Sample Size(n)=7
Confidence Interval = [ 0.1157 ± t a/2 ( 0.0513/ Sqrt ( 7) ) ]
= [ 0.1157 - 3.143 * (0.019) , 0.1157 + 3.143 * (0.019) ]
= [ 0.055,0.177 ]
Interpretations:
1) We are 98% sure that the interval [0.055 , 0.177 ] contains the true population mean
2) If a large number of samples are collected, and a confidence interval is created
for each sample, 98% of these intervals will contains the true population mean
Yes. because the confidence inteval cotains 0.165 g/ml
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