Suppose a basketball player is a good free throw shooter and makes 80% of her fr

Question

Suppose a basketball player is a good free throw shooter and makes 80% of her free throws (that is, she has a 80% chance of making a single free throw). Assume that free throw shots are independent of one another and suppose the player is awarded three free throws. Find the probability that she misses all three free throws. 0.0080 0.3333 0.1667 0.20 Find the probability that she makes at least one free throw. 0.9920 0.6667 0.8333 0.80 Build a tree diagram or use binomial probabilities in order to determine the probability that she makes exactly two out of three free throws. 0.3333 0.6667 0.3840 0.8333 Let X be a binomial random variable with n = 10 and p = 0.6. Find P(X = 5) 0.2007 0.6000 0.0600 0.8333 Find P(X lessthanorequalto 5) 0.3669 0.6331 0.8333 0.1667 Find P(X > 5) 0.3669 0.6331 0.8333 0.1667 Past studies have shown that 30% of all surgical patients who receive a particular type of anesthetic experience mild post-operative nausea. Suppose that 7 patients are scheduled to receive this type of anesthetic today, and let X = the number who will experience post-operative nausea. Find the probability that exactly four of the patients experience post-operative nausea. 0.4286 0.0972 0.0270 0.30 Find the probability that fewer than four of the patients experience post-operative nausea. 0.2269 0.1260 0.7731 0.8740 Find the probability that at least four of the patients experience post-operative nausea. 0.2269 0.1260 0.7731 s 0.8740

Explanation / Answer

Baseball Question

Probability of free throw p = 0.8

Probability of missing a free throw 1-p = 0.2

8)

Probability that all 3 free throws will miss = 0.2*0.2*0.2 = 0.008 (Option A)

9)

At least 1 free throw = 1 - 0.008 = 0.992 (Option A)

10)

Probability of making exactly two free throws = 3C2 * (0.8)^2 * (0.2) = 0.384 (Option C)

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