W. Brase, Understanding Ex WA Hwks 6.1 STA x c Search Q&A; IChegg.cc x my emich

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W. Brase, Understanding Ex WA Hwks 6.1 STA x c Search Q&A; IChegg.cc x my emich myemich x M Phone number seisha x akon don't matter You x Section www.webassign.net/weblStudentIAssignment -Responses/submit?del 15806416 p 6.1 USA Today reported that approximately 25% of state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisonersup for parole. Let all x number of out of five on parole who become repeat offenders. (a) Find the probability that one or more of the five parolees will be repeat ofenders. (Round your answer to three decimal place How does this number relate to the probability that none of the parolees wil be repeat offenders? O These probabilities are the same. This is the complement of the probability of no repeat offenders. This is twice the probability of no repeat offenders. These probabilities are not related to each other. This is five times the probability of no repeat offenders. (b) Find the probability that two or more of the five parolees will be repeat offenders. Round your answer to three decimal places.) (c) Find the probability that four or more of the five parolees will be repeat offenders (Round your answer to three omalpaces (d) Compute w, the expected number of repeat omenders out of five. (Round your answer to three decimal places.) (e) Compute o, the standard deviation of the number of repeat offenders out five. (Round your answer to two decimal places) of

Explanation / Answer

a)P(x>=1)=1-P(x=0)=1-0.224=0.776

b)This is the complement of repeat offenders

c)P(X>=2)=1-P(X=0)-P(X=1)=1-0.224-0.371=0.405

d)Mean=5*0.25=1.25

e)SD=sqrt(5*0.25*0.75)=0.9682

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