A box contain 3 good cards and 4 bad (penalty) cards. A chooser a card and then

Question

A box contain 3 good cards and 4 bad (penalty) cards. A chooser a card and then player B choose a card. The cards are drawn without replacement. Find the probability of the following events remembering to justify your answer with equations (and a Venn diagram if you would like). P(A good) P(B good | A good) P(B good | A bad) P(B good intersection A good) P(B good intersection A bad) P(B good) P(A good | B good) problem 2, but this time assume that player A looks at his/her card, replace it in the box, and remixes or shuffles the cards before player B drawn. A big bowl contains five blue balls and three red balls. A boy draws a ball and then draws another without replacement. Find the following probabilities. P(2 blue balls) P(1 blue and 1 red ball) P(at least 1 blue ball) p(2 red ball)

Explanation / Answer

A) AS THERE are 3 good out of 7; hence P(Agood) =3/7

b)as now it is done with replacement, hence event A and B are independent.

therefore P(Bgood|Agood) =P(Bgood) =3/7

c) referring above,

P(Bgood|Abad) =P(Bgood) =3/7

d) P(BgoodnAgood) =(3/7)*(3/7) =9/49

e)P(BgoodnABad) =P(Bgood)*P(A bad) =(3/7)*(4/7)=12/49

f)P(Bgood) =3/7

g)P(Agood|Bgood) =3/7

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