Four women’s college basketball teams are participating in a single-elimination

Question

Four women’s college basketball teams are participating in a single-elimination holiday basketball tournament. If one team is favored in its semifinal match by odds of 1.70 to 1.30 and another squad is favored in its contest by odds of 2.60 to 1.40, what is the probability that: a. Both favored teams win their games? (Round your answer to 4 decimal places.) Probability b. Neither favored team wins its game? (Round your answer to 4 decimal places.) Probability c. At least one of the favored teams wins its game? (Round your answer to 4 decimal places.) Probability

Explanation / Answer

let the favored teams be team 1 and team 2

probality of team 1 winning = 1.7/(1.7+1.3) = 1.7/3 = 0.5667

probabity that team 2 winning = 2.6/(2.6+1.4) = 2.6/4 = 0.65

probability that Both favored teams win their games = 0.5667*0.65 = 0.3684

b) Probability that Neither favored team wins its game = (1-0.5667)(1-0.65) = 0.1517

c)Probability that At least one of the favored teams wins its game = 1- Probability that Neither favored team wins its game = 1-0.1517 = 0.8483

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