The time spent (in days) waiting for a kidney transplant for people ages 35-49 c

Question

The time spent (in days) waiting for a kidney transplant for people ages 35-49 can be approximiated by the normal distribution, as shown in the figure to the right.

95th

(b) What waiting time represents the first quartile?

mu equals 1679=1679

sigma equals 213.6=213.6

The time spent (in days) waiting for a kidney transplant for people ages 35-49 can be approximiated by the normal distribution, as shown in the figure to the right.

95th

(b) What waiting time represents the first quartile?

mu equals 1679=1679

sigma equals 213.6=213.6

Explanation / Answer

mean = = 1679

standard deviation = = 213.6

a)let the time representing 95 percentile be T

P(t<T) = 0.95

Using Z-table ,z value for p=0.95 is 1.645

1.645 = (T-1679)/213.6

T-1679 = 1.645*213.6 => T = 1679+1.645*213.6 = 2030.37

waiting time for 95th percentile = 2030.37

b)let time for first quartile be q

P(t<q) = 0.25

z value for p=o.25 is -0.675

-0.675 = (q-1679)/213.6

q = 1679-0.675*213.6 = 1534.82

waiting time representing the first quartile = 1534.82

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