An airflow experiment compared two different terminal devices that are used to d

Question

An airflow experiment compared two different terminal devices that are used to diffuse air throughout a space thereby provide heating and/or cooling.Fifty diffusers of each type were randomly selected in a building that contained 1100 diffusers per floor. data below presents the airflow measurements in cubic feet per minute, obtained in this experiment,

Based on the data above, compute the following for "Crane":   1DP means having 1 digit after decimal point in your solution.

Arithmetic mean=?? (1DP);

Median=???;

Midrange= ???(1DP) ;

first quartile=???;

third quartile=????;

midhinge=???? (1DP) ;

interquartile range=???;

variance= ???(0DP);

standard deviation=???? (1DP)

Crane Krueger 245 275 230 225 180 230 200 240 180 205 155 125 195 265 220 225 195 190 200 275 225 240 240 205 200 150 240 265 285 230 250 300 295 275 295 240 270 245 285 250 125 100 255 270 190 245 275 230 280 225 205 285 215 275 370 350 265 200 290 255 310 265 250 230 215 250 270 195 295 240 210 225 235 230 160 290 235 230 280 250 250 225 240 275 295 205 285 245 290 350 250 300 310 275 290 260 300 305 300 230

Explanation / Answer

By using R-software

Command for this problem

Note :-Here, all data select and paste in MS-Excel and then open R-software and type command "c=scan("clipboard")" in R-software.

Or c=c( 245, 230, 180, 200, 180, 155, 195, 220, 195, 200, 225, 240, 200, 240, 285, 250, 295, 295, 270,
285, 125, 255, 190, 275, 280, 205, 215, 370, 265, 290, 310, 250, 215, 270, 295, 210, 235, 160,
235, 280, 250, 240, 295, 285, 290, 250, 310, 290, 300, 300)

c

n=length(c);n

A.M=mean(c);A.M
Median=median(c)
Median
ma=max(c);ma
mi=min(c);mi
Range=ma-mi;Range
MR=(ma+mi)/2;MR # midrange
Q1=quantile(c,0.25);Q1
Q3=quantile(c,0.75);Q3
IQR=Q3-Q1;IQR # interquartile range
midhinge=(Q1+Q3)/2
midhinge
s=var(c);s
var=((n-1)/n)*s
var
sd=sqrt(var);sd # standard deviation

Output

>c=scan("clipboard")

> c

[1] 245 230 180 200 180 155 195 220 195 200 225 240 200 240 285 250 295 295 270
[20] 285 125 255 190 275 280 205 215 370 265 290 310 250 215 270 295 210 235 160
[39] 235 280 250 240 295 285 290 250 310 290 300 300
> n=length(c);n
[1] 50
> A.M=mean(c);A.M
[1] 246.5
> Median=median(c)
> Median
[1] 250
> ma=max(c);ma
[1] 370
> mi=min(c);mi
[1] 125
> Range=ma-mi;Range
[1] 245
> MR=(ma+mi)/2;MR # midrange
[1] 247.5
> Q1=quantile(c,0.25);Q1
25%
211.25
> Q3=quantile(c,0.75);Q3
75%
285
> IQR=Q3-Q1;IQR # interquartile range
75%
73.75
> midhinge=(Q1+Q3)/2
> midhinge
25%
248.1
> s=var(c);s
[1] 2336.99
> var=((n-1)/n)*s
> var
[1] 2290
> sd=sqrt(var);sd # standard deviation
[1] 47.8

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