The following joint distribution that has been constructed using data from the 1

Question

The following joint distribution that has been constructed using data from the 1995 National Health Survey conducted by the Australian Bureau of Statistics. This is a large, rationally represented survey of Australians. The data in the Table refer to whether an individual has used any medications in the last 2 weeks prior to interview and their self-assessed health status (SAHS). For SAHS individuals are asked to rate their current health on a five-level scale ranging from poor to excellent. Table; Joint frequency distribution of self-assessed health and use of medications for Australians in 1995 Using the distribution as an estimate of the population distribution, which of the following is not correct? Select one: The probability that a randomly selected Australian did not use medication In the last two weeks is 0.354 The probability that a randomly selected Australian Is In fair health is 0.119 Australians In poor health are much more likely to be using medications than not using medications The conditional probability of being in excellent health given not using medications is equal to the probability of being in excellent health.

Explanation / Answer

(s) P(did not use medication) = 35.4/100 = 0.354 (true)

(b) P(fair health) = 11.9/100 = 0.119 (true)

(c) P(use medication | poor health) = 3.5/3.9 = 0.897 and P(don't use medication | poor health)
= 0.4/3.9 = 0.103

Australians in poor health are much more likely to use medication than not use medication (true)

(d) P(excellent health | not using medication) = 9.4/35.4 = 0.266

P(excellent health) = 20.1/100 = 0.201

These two are not equal.

So statement (d) is false.

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