Let y denote the number of broken eggs in a randomly selected carton of one doze

Question

Let y denote the number of broken eggs in a randomly selected carton of one dozen eggs, suppose that the probability distribution of y is as follows. Only y values of 0, 1, 2, 3, and 4 have positive probabilities what is p(4)? How would you interpret p(1) - 0.20? The proportion of eggs that will be in each carton from the population is 0.20. If you check a large number of cartons, the that will have at most one broker egg will equal 0.20. The probability of one randomly carton having broken eggs in it is 0.20. In the long run, the proportion of cartons that have exactly one broken egg will equal 0.20. Calculation p(x greaterthanorequalto z), the probability that the carton contain at most two broken eggs. Interpret this probability. The proportion of eggs that will be broken in any two carton from the population in0.95. The probability of has randomly certain having broken eggs in them in 0.95. If you check a large number of cartons, the proportion that will have at most two broken eggs will equal 0.95. In the long run, the proportion of that have exactly two broken eggs will equal 0.95. Calculation p(y greaterthanorequalto z), the probability that the carton contain fewer than two broken eggs. Why is this smaller that the probability part(c)? This probability is less than probability in part (c) increase the two probability are the same for this distribution. This probability is less than probability is part (c) because the proportion of eggs with any exact number of broken eggs is This probability is less than the probability is part(c) because in probability distribution, is always greater than This probability is less than the probability is part (c) because the event y = 2 is now not induced. What is the probability that the carton contains exactly 10 unbroken eggs? What is the probability that at least 10 eggs are unbroken?

Explanation / Answer

e) The Carton contains exactly 10 unbroken eggs is same same the carton contains exactly 2 broken eggs as a carton contains one dozen eggs. so the value of y is 2.

And the probability is 0.11

f) At least 10 eggs are unbroken. Is same as saying that 10, 11 or 12 eggs are unbroken.

Thus probability that atleast 10 are unbroken is equal to probability that at most 2 are broken

And that probability is 0.64+0.20+0.11=0.95

So the required probability is 0.95

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