Let us play the modified “red dragon” game with your opponent. It is a two-playe

Question

Let us play the modified “red dragon” game with your opponent. It is a two-player game and each player takes turn. Initially, there are a total of 23 green dragons and one red dragon. The goal of the game is to take the red dragon; in other words, the player who has the red dragon will win. However, no one can take the red dragon unless all the green dragons are gone. The game goes like this. In each player's turn, (s)he can take up to four dragon(s), but (s)he cannot take none. In other words, (s)he can take one, two, three, or four dragon in each turn. The game concludes when there is only one (red) dragon left, and the player who takes the last (red) dragon is the winner.

Now, suppose that you take turn first, please use your best reasoning ability to design a strategy to guarantee a win no matter how your "evil but smart" opponent will react.

Explanation / Answer

Basically, there are 24 dragons.

who says 24 first wins.

take it a mug up, you will get the catch;

let's take 4 at once, so the add one to it. we play with multiple of 5 like (24-5n)

so these are the number we have to land on

first on 4, then 9,14,19 and last 24

we start with 4,& choose the next number accordingly.

and we will get 24 & "evil but smart" crown

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