Do Arni HopperMicrosolt Edge d:470567498&questionld; 21&flushed-true;ⅆ 49034

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Do Arni HopperMicrosolt Edge d:470567498&questionld; 21&flushed-true;ⅆ 49034 mathdcom/student/PlayerHomeworkaspx?homeworld-470567 MA TH2053 901&902 (Spring 2018) B Rickard Homework: Homework #1 (chapter 23) Score: 0 of 1pt (X) 2.1.19 Use the echelon method to solve the given system of two equations in two unknowns. Check your answers 1 of 69 (13 complete) 2 - 24 Select the correct choice below and fill in any answer boxes in your choice A. The solution of the system is Simplify your answer Type an ordered pair.) B. There are infinitely many solutions The solution is (y) where y is any real number O C. There is no solution Click to select and enter your answers) and then cick Check Ansuwer All parts showing ear All

Explanation / Answer

Hi!

Notice that y has a co-efficient of 1 in both the equations. So we can directly subtract both the equations to eliminate y.

(1) - (2) --->

x/2 - x/7 = 1/2 -(-24/7)

5x/14 = 55/14

Cancel out the 14 in the denominator.

5x = 55.

x = 11.

There we have the value of x = 11. Now we need to back substitute the value of x into any of the equations to get the value of y. Let's substitute x = 11 into Equation (1) .

(11/2) + y = (1/2)

y = (1/2) - (11/2)

y = (-10/2)

y = -5.

There we have the value of y = -5.

We can double check by substituting x = 11 into Equation 2 as well.

(11/7) + y = (-24/7)

y = (-24 -11/7)

y = (-35/7)

y = -5

Cheers!

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