The number of bacteria in a flask grows according to the differential equation:

Question

The number of bacteria in a flask grows according to the differential equation: dy/dt=0.1y In this question, time is measured in hours and the number of bacteria, y, is measured in millions. The number of bacteria at time t = 0 is 10 million. Enter a formula for the number of bacteria at time t y = What is the value of the growth constant? Growth constant : ______per hour. How long does it take for the number of bacteria to double? (Enter your answer correct to two decimal places.) Doubling time : _________ hours. How many million bacteria will be present after 5 hours have passed? (Enter your answer correct to one decimal place.) Number present after 5 hours : ______ million.

Explanation / Answer

N = 10 e^(-0.1t) million 0.1 per hour

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