19.-/1 pointsTG nterAIgHS 5.7.E02. EXAMPLE 2 Factor: 648-25b2. The terms of this

Question

19.-/1 pointsTG nterAIgHS 5.7.E02. EXAMPLE 2 Factor: 648-25b2. The terms of this binomial do not have a common factor (other than 1). The only option is to attempt to factor it as a difference of two squares. Strategy Why If a binomial is a difference of two squares, we can factor it using a special product rule. Solution We can write 64a 25b2 in the form (802)2- and use the formula for factoring the difference of two squares. (Ba2)2-(5b2 (8a2 +5b) (Ba-56) Self Check 2 Factor: 64 s2 20.-/1 pointsTGInterAlg5 5.7.071. Factor the difference of cubes. Factor out the GCF first. 5x5 625x2

Explanation / Answer

1) 64a^4 - 25b^2

( 8a^2)^2 - ( 5b)^2

= ( 8a^2 - 5b ) ( 8a^2 + 5b )

2) 64r^4 - s^2

= ( 8r^2)^2 - (s)^2

= ( 8r^2 - s ) ( 8r^2 + s )

3) 5x^5 - 625 x^2

5x^2 ( x^3 - 125 )

= 5x^2 ( x^3 - 5^3 )

= 5x^2 ( x - 5 ) ( x^2 + 5x + 25 )

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.