App Store l LTE 9:11 AM Alg2A Pretest.pdf Date Skills Test Prerequisite Skills T

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App Store l LTE 9:11 AM Alg2A Pretest.pdf Date Skills Test Prerequisite Skills Test (continued) 13 If x)7+.compate 3) 14. On a certain day there was a near consdant snow fall rate of 0 50 inch prbour Afier 4 hours there were 10 inches of smow on the ground (inclading ome from the day before). Write an oquation that models the amount of snowfall in nches y afer x hours 15. You are traveling away from bme at a constant speed Ahr 3 hours you are miles from home and equation that models y, your distance (in miles) from home after x hours miles trom home. Winite an after 7 hours Write an equation representing the translation of fx)7x+3 down 17. The average attiendance of a certain fitness class that mects daily for the Er days are given: 4, 10, 16, and 22 Write a formala for the gencral tem a which models the patem n Exercises 18-20, solve the system using any method 18. y-3+2 ?.7x-10 19. 3s+2y- y-3x+1 20. 2x2ys y-10 2lty( 22. Simplify Algebra 2 3

Explanation / Answer

13) Given, f(x) = 7x2+5

Then, f(3) = 7*32+5 = 7*9+5 = 68

i.e., f(3) = 68

14) By the given condition, we have,

y = [10-(4*0.50)]+(0.50*x)

i.e., y = [10-2]+(0.50*x)

i.e., y = 8+(0.50*x)

Multiplying both sides by 2 we get,

2y = 16+x

Therefore, the required equation that models the amount of snowfall in inches y after x hours is : 2y = 16+x.

15) Let the equation of the given model be y = mx+c, where y = distance from home, m = speed, x = time of travelling, c = distance from home where i start travelling.

By the given conditions we have, 3m+c = 60..........(i) and 7m+c = 160...........(ii)

Subtracting (i) from (ii) we get, 4m = 100 ,i.e., m = 25

Putting this in (i) we get, c = -15

c is negative implies that the starting point is in the opposite direction of the travelling direction with respect to the home.

Therefore, the required equation is : y = 25x-15.

16) The required equation is : y = (7x+3)-4 ,i.e., y = 7x-1.

17) Here, a1 = 4, a2 = 10, a3 = 16, a4 = 22.

Now, a1 = 4+0 ,i.e., a1 = 4+6*(1-1)

a2 = 4+6 ,i.e., a2 = 4+6*(2-1)

a3 = 4+12 ,i.e., a3 = 4+6*(3-1)

a4 = 4+18 ,i.e., a4 = 4+6*(4-1)

Therefore, the required formula for the general term is : an = 4+6*(n-1).

18) Given system of equations is :

y = 3x+2..........(i)

y = 7x-10..........(ii)

From (i) and (ii) we have, 3x+2 = 7x-10

i.e., 3x-7x = -10-2

i.e., -4x = -12

i.e., x = 3

Putting this in (i) we get, y = 3*3+2 ,i.e., y = 11

Therefore, solution is : x = 3 and y = 11.

19) Given system of equations is :

3x+2y = 8..........(i)

y = 3x+1............(ii)

From (i) and (ii) we get, 3x+2*(3x+1) = 8

i.e., 3x+6x+2 = 8

i.e., 9x = 6

i.e., x = 6/9

i.e., x = 2/3

Putting this in (ii) we get, y = 3*(2/3)+1 ,i.e., y = 3

Therefore, the solution is : x = 2/3 and y = 3.

20) Given system of equations is :

2x+2y = 8........(i)

3x+y = 10.........(ii)

Dividing (i) by 2 and then subtracting from (ii) we get, 2x = 6 ,i.e., x = 3

Putting this in (ii) we get, 3*3+y = 10 ,i.e., y = 1

Therefore, the solution is : x = 3 and y = 1.

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