Edit View History Bookmarks Window Help MAT G172-College Algebra-Summer18-Sessio
ID: 3185816 • Letter: E
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Edit View History Bookmarks Window Help MAT G172-College Algebra-Summer18-Session 1 Quiz: Quiz 3 - Chapter 3 This Question: 1 pt 401 25 (3 complete) ? Thia Quiz: 25 pts posst Suppose that the manufacturer of a gas clothes dryer has found that when the unit price is p dollars,the revene R On dolars) is Rp)-4p+4.000p (a) At what prices p is revenue zero? (b) For what range of prices will revenue exceed $800,0001? (a) At what prices p is revenue zero? The revenue equais zero when p is $0,1000 (Use a comma to separate answers, but do not use commas in any individual numbors) (b) For what range of prices will revenue exceed $800,000? Type your answer in interval notation. Round to the nearest cent as needed) e Enter your answer in each of the answer baxes. 50mn of 06/17/18 11:59pm | 183058985,%20false);"Explanation / Answer
Given that the revenue, R(p) = --4p2+4000p
a) given condition is that the value of the revenue is zero.
Implies R(p) = 0, So
-4 p2 + 4000p = 0
-4 p2 = -4000p
P2 = 1000P
P = 1000 or P = 0 is the answer.
b) Now, revenue R(p) exceeds 800,000
Implies, R(p) > 800,000
So, --4 p2 +400p > 800,000
-4 p2 + 4000p-800000 >0
Multiplying the whole equation by -1, the sign changes and we get,
4 p2 -4000p+800,000 < 0
Common out 4, we get
p2 -1000p+200,000 <0
(P-276.39)(P-723.61) <0
Implies, the range will be ,
276.39<P<723.61 is the range.
Interval: (276.39, 723.61)
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