ndard deviation of a list of numbers is a measure of how much the s deviate from

Question

ndard deviation of a list of numbers is a measure of how much the s deviate from the average. If the standard deviation is small, the numbers are clustered close to the average. If the standard deviation is large, he numbers are scattered far from the average. The standard deviation, S, of a ist of N numbers a is defined as follawerag = (x,-x)2 where x is the average of the N numbers x1, x2, .. that takes a partially filled array of numbers as its arguments and returns the standard deviation of the numbers in the partially filled array. Since a partially filled array requires two arguments, the function will actually have two formal parameters: an array parameter and a formal parameter of type int that gives the number of array in the array will be of type double. Embed your function in a suitable test program. Define a function positions used. The numbers nto an array with base

Explanation / Answer

#include #include using namespace std; float average (float vector[], int size); float deviation( float sum, float average,float N ); float sum (float vector[], int size); int main () { ifstream inputfile; float N; int size = 0; const int Num_List = 1000; float summ, avg; double standDeviation [Num_List]; inputfile >> N; while((!inputfile.eof()) && (size> N; } summ = sum (standDeviation, size); avg = average(standDeviation, size); cout.setf(ios::fixed); cout.setf(ios::showpoint); cout.precision(3); cout

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