Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

11. The Scheffe test sleep apnea is a sleep disorder characterized by pauses in

ID: 3183602 • Letter: 1

Question

11. The Scheffe test sleep apnea is a sleep disorder characterized by pauses in breathing during sleep. Children with sleep apnea have behavior problems, induding hyperactivity, inattention, and aggression, as well as impaired learning and diminished academic performance. The removal of tonsils and adenoids that are enlarged, causing the obstruction of the airways, isone of the most common treatments for pediatric sleep apnea. A clinical psychologist studies the effects of tonsillectomy and adenoidectomy on hyperactive behavior. Her quasi-experiment indudes three groups of 11 children. The first group of children does not have sleep apnea, the second group has untreated sleep apnea, and the third group has sleep apnea treated by tonsilectomies and adenoidectomies. Hyperactivity was measured using teacher reports on the Conners Rating scale. The sample means and sums of squared deviations of the scores for each of the three groups are presented in the table that follows. Sample Mean Sum of Squares Group 0.3240 No sleep apnea 0.4410 0.45 Untreated sleep apnea 0.2250 0.31 Treated sleep apnea After collecting the data, the clinical psychologist analyzes the data using an ANovA. The results of her analysis are presented in the ANOVA table that follows. ANOVA Table Degrees of Source of Sum of Squares Freedom Mean Square Variation 7.02 0.2316 0.4631 Between Treatments 0.0330 0.9900 Within Treatments 1.4531 Total The critical value of F when or 01 is 5.390, meaning the critical region consists of all F-ratios greater than 5.390 The F-ratio is greater than this critical value, so you know that at least one difference exists among the treatments. Since than two groups are involved, the psychologist is interested in determining which groups are different. more The Scheffe test will be used to evaluate the pairs. Call the no sleep apnea group A, the untreated sleep apnea group B, and the treated sleep apnea group C. Start with the will evaluate the difference between the no sieep apnea group A) and the calculations you need to untreated sleep apnea group (B). The SS batween AB is 0.1238 The Fs venus is 5.39 (Hint: Recall that you can use the sample size treatment tn 11) and the treatment mean to compute each for each treatment total (T).)

Explanation / Answer

No sleep apnea:-0.60*11=6.6

Untreated sleep apnea:-0.45*11=4.95

SSAB=6.6^2+4.95^2/11-11.55^2/22=6.1875-6.06375=0.12375

MSbetween=0.12375/2=0.061875, Fcomparision=0.061875/0.0330=1.875

F is smaller than 5.39 and hence cannot reject the null hypothesis.

No sleep apnea:-0.60*11=6.6

Treated sleep apnea:-0.31*11=3.41

SSAC=6.6^2+3.41^2/11-10.01^2/22=5.0171-4.55455=0.46255

MSbetween=0.46255/2=0.231275, Fcomparision=0.231275/0.0330=7.01

F is greater than 5.39 and hence reject the null hypothesis.

Untreated sleep apnea=0.45*11=4.95

Treated sleep apnea:-0.31*11=3.41

SSBC=4.95^2+3.41^2/11-8.36^2/22=3.2846-3.1768=0.1078

MSbetween=0.1078/2=0.0539, Fcomparision=0.0539/0.0330=1.63

F is smaller than 5.39 and hence cannot reject the null hypothesis.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Chat Now And Get Quote